Obtener la fórmula empírica de un compuesto cuya composición centesimal reporta: Cr: 26,53 % , S: 24,52 % y O: 48,96%. Dato: m. A. [Cr= 52 , S= 32]

The empirical formula of the compound becomes

Explanation:

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

Let the mass of the compound be 100 g

Given values:

% of Cr = 26.53%

% of S = 24.52%

% of O = 48.96%

Mass of Cr = 26.53 g

Mass of S = 24.52 g

Mass of O = 48.96 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

......(1)

To formulate the empirical formula, we need to follow some steps:

Molar mass of Cr = 52 g/mol

Molar mass of S = 32 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 0.510 moles

Multiplying the mole fraction of all the elements by 2, in order to make it as a whole number

The ratio of Cr : S : O = 2 : 3 : 12

Hence, the empirical formula of the compound becomes

11 players on a field that has a maximum of 11 players

answer; talc and gypsum;