A student dissolved 3.50g of copper (II) nitrate in water and mixed it with a solution of sodium carbonate. The student recovered 1.89g of copper carbonate precipitate. If the theoretical yield is 2.35g, what is the percent yield

If the theoretical yield is 2.35g then the percent yield is 80.4%

Explanation:

Given: Actual yield = 1.89 g

Theoretical yield = 2.35 g

Formula used to calculate the percentage yield is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that if the theoretical yield is 2.35g then the percent yield is 80.4%

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.