UESTION 6 (Start on a new page.) 1 Potassium permanganate, KMno., burns with a bright flame when a few drops of glycerine are added to it. The incomplete equation for the reaction is: 14KMnO, + glycerine 7K. CO, +7Mn0, +xCO, + 16H, O 6.1.1 Define the term molar mass. (2) 6.1.2 The composition of glycerine is as follows: 39,1396 carbon, 8,7% hydrogen, 52,17% oxygen Determine the EMPIRICAL formula of glycerine. Show ALL calculations. (6) 6.13 Write down the value of x in the equation above if the MOLECULAR formula of glycenne is C, H,O, (1) 6.1.4 Calculate the mass of Mngo, that can be prepared if 18 g of KMnO, reacts with excess glycerine. The balanced equation for the reaction of sodium chloride, NaCl, with sulphuric acid, H2SO4, is as follows: 2NaCl(s) + H2SO.(aq) Na, SO(aq) + 2HCU9) During a reaction, 1,5 g of an impure sample of sodium chloride reacts with 100 cm sulphuric acid of concentration 0,1 mol dm at room temperature 6.2.1 (2) Define the term concentration. Calculate the number of moles of sulphunc acid used in the reaction above. 6.22 (3) On completion of the reaction it is found that 460 сm of HCI gas has formed. 6.2.3 Calculate the percentage purity of the sodium chloride. Use 24.45 dmº as the molar gas volume (V.) at room temperature (6) [24]​

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  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.