How many grams of Br are in 345g of CaBr2?

276g of Br are present

Explanation:

To solve this question we need to find the moles of CaBr2 using its molar mass -CaBr2: 199.89g/mol-. As 1 mole of CaBr2 contains 2 moles of Br we can find the moles of Br and its mass:

Moles CaBr2:

345g * (1mol/199.89g) = 1.7259 moles CaBr2

Moles Br:

1.7259 moles CaBr2 * (2mol Br / 1mol CaBr2) = 3.4519 moles Br

Mass Br -Molar mass: 79.904g/mol-

3.4519 moles Br * (79.904g/mol) = 276g of Br are present

answer; economic order quantity;

1 a

2 d

3 a

4 c

explanation: