For a certain chemical reaction, the standard Gibbs free energy of reaction is 55.4 kJ. Calculate the temperature at which the equilibrium constant k = 9.1 x 10^-11.

288 K

Explanation:

Step 1: Given data

Step 2: Calculate the temperature at which the equilibrium constant is 9.1 × 10⁻¹¹

We will use the following expression.

ΔG° = -R × T × lnK

where,

R: ideal gas constant

T: absolute temperature

T = -ΔG° /R × lnK

T = -(55.4 × 10³ J/mol) /(8.314 J/mol.K) × ln 9.1 × 10⁻¹¹ = 288 K

it means there are 3 atoms of oxygen