Chemistry, 05.07.2021 19:40 deanlmartin
HI dissociates to form I2 and H2: 2HI(g) → H2(g) + I2(g) If the concentration of HI changes at a rate of –0.45 M/s, what is the rate of appearance of I2(g)?
Answers: 3
![\frac{d[HI]}{dt}=-0.45M/s](/tpl/images/1389/3507/a4de2.png)
![-\frac{1}{2}\frac{d[HI]}{dt}=\frac{d[I_2]}{dt}=\frac{d[H_2]}{dt}](/tpl/images/1389/3507/a49b9.png)
![-\frac{1}{2}\frac{d[HI]}{dt}=\frac{d[I_2]}{dt}](/tpl/images/1389/3507/60368.png)
![-\frac{1}{2}\times (-0.45)=\frac{d[I_2]}{dt}](/tpl/images/1389/3507/2eb3f.png)
![\frac{d[I_2]}{dt}=0.225M/s](/tpl/images/1389/3507/6ec15.png)
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HI dissociates to form I2 and H2: 2HI(g) → H2(g) + I2(g) If the concentration of HI changes at a rat...
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