A solution of hydrochloric acid had a hydrogen ion concentration of 1.0 mol/dm3 Water was added to hydrochloric acid until the ph increased by 1
What was the hydrogen ion concentration of the hydrochloric acid after had been added?

pH = -log[H+]

Where [H+] = Hydrogen ion concentration

In this case,

[H+] = 1 × 10^(-2) = 10^(-2)

log{10^(-2)} = -2

-log{10^(-2)} = -(-2) = 2

pH = -log{10^(-2)} = 2

and hi.!!!

0.1

Explanation:

Hydrogen ion concentration can be calculated using the formula [H+] = 10^-pH

pH can be concentrated using ph = -log[H+]

let's calculate the initial pH before anything was added: pH = -log(1) = 0

it increased by 1 so the final pH is 1.

Now we'll find the [H+] of a solution with a pH of 1:

concentration = 10^(-1) = 0.1

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)