g The theoretical yield of a certain reaction is 123 g of Al2O3. If the actual yield when the experiment is performed is 0.209 mol Al2O3, what is the percent yield

Percent yield = 17.3%

Explanation:

The percent yield is defined as 100 times the ratio between actual yield in grams and theoretical yield in grams (123g).

Percent Yield = Actual Yield / Theoretical yield (123g) * 100

To find actual yield we need to convert the 0.209moles to grams:

Actual yield -Molar mass Al2O3: 101.96g/mol-

0.209mol * (101.96g/mol) = 21.3g

Percent yield = 21.3g / 123g * 100

Percent yield = 17.3%

i think it is true since you can test the answer and can use observations to complete it.