Scoring Scheme: 3-3-2-1 Given the starting solution had a concentration of 1.25 M, how many moles of Co[H2O]6Cl2 were available in the amount of starting solution you used

The solution has 0.00994 moles of Co[H2O]6Cl2

Explanation:

Complete question: Given the starting solution had a concentration of 1.25 M, how many moles of Co[H2O]6Cl2 were available in the amount of starting solution you used?

mL= 7.95

Step 1: Data given

Concentration of the starting solution = 1.25 M

Starting solution = Co[H2O]6Cl2

Step 2: Calculate molar mass of Co[H2O]6Cl2

Atomic mass of Co = 58.93 g/mol

Atomic mass of H = 1.01 g/mol

Atomic mass of O = 16.00 g/mol

atomic mass of Cl = 35.45 g/mol

Molar mass of Co[H2O]6Cl2 =

1*58.93 + 12*1.01 + 6*16.00 + 2*35.45 = 237.95 g/mol

Step 3: Calculate number of moles

C = n/v

⇒with C = the Concentration of the starting solution = 1.25 M

⇒with n= the number of moles = to be determined

⇒with v = the volume = 7.95 mL = 0.00795 L

n = C * V

n = 1.25 M * 0.00795 L

n = 0.00994 moles

The solution has 0.00994 moles of Co[H2O]6Cl2

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .