What is the pH of a 0.85 M solution of N(CH3)3? Note: Kb = 6.4 x 10^-5 for N(CH3)3
Include a reaction and a Ka or Kb expression

Ph of a 95 = 74 of KN

This is what i found on google “when one phosphate group is removed by breaking a phosphoanhydride bond in a process called hydrolysis, energy is released, and atp is converted to adenosine diphosphate (adp). likewise, energy is also released when a phosphate is removed from adp to form adenosine monophosphate (amp).” i hope this you .