g Aluminum sulfite reacts with sodium hydroxide to form sodium sulfite and aluminum hydroxide according to the following equation. Al2(SO3)3 6 NaOH> 3 Na2SO3 2 Al(OH)3a)Determine the limiting reactant if 18.0 g of Al2(SO3)3reacts with 16.0 g of NaOH. b)Determine the number of moles and mass of Al(OH)3produced. c)Determine the number of molesand mass of Na2SO3produced. d)Determine the grams of excess reagent left over in the reaction.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na

Contained in chromosomes which are located in the nucleus of the cell.

That is a lot of moles that you have