If the half-life of a radioactive substances is 590 million years and you have 40 atoms of it, how many half-lives will have passed when 5 atoms remain

3

Explanation:

Applying,

= R/R'............... Equation 1

Where n' = number of halflives that have passed, R = Original atom of the substance, R' = atom of the substance left after decay.

From the question,

Given: R = 40 atoms, R' = 5 atoms

Substitute these values into equation 1

= 40/5

= 8

= 2³

Equation the base,

n' = 3

e

explanation:

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong