Find the mass of Mg required to react with 5.00 g of HCl and produce MgCl2 and H2 using the following equation: Mg(s) + 2HCl(aq) → MgCl2(aq) +H2(g)

1.64 g of Mg

Explanation:

The balanced equation for the reaction is given below:

Mg + 2HCl —> MgCl₂ + H₂

Next, we shall determine the masses of Mg and HCl that reacted from the balanced equation. This can be obtained as follow:

Molar mass of Mg = 24 g/mol

Mass of Mg from the balanced equation = 1 × 24 = 24 g

Molar mass of HCl = 1 +35.5

= 36.5 g/mol

Mass of HCl from the balanced equation = 2 × 36.5 = 73 g

SUMMARY:

From the balanced equation above,

24 g of Mg reacted with 73 g of HCl.

Finally, we shall determine the mass of Mg required to react with 5 g of HCl. This can be obtained as illustrated below:

From the balanced equation above,

24 g of Mg reacted with 73 g of HCl.

Therefore, Xg of Mg will react with 5 g of HCl i.e

Xg of Mg = (24 × 5)/ 73

Xg of Mg = 1.64 g

Thus, 1.64 g of Mg is required for the reaction.

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;