What is the concentration of HI in the final solution when 65 mL of a 3.0 M HI solution is diluted with pure water to a total volume of 0.15 L g?

The concentration of HI in the final solution is 1.3 M.

Explanation:

Dilution is the reduction in concentration of a chemical in a solution. It is achieved by adding more solvent to the same amount of solute.

In other words, in a dilution, the amount of solute does not change, but the volume of the solvent does: as more solvent is added, the concentration of the solute decreases, since the volume (and weight) of the solution increases.

When dealing with dilution you will use the following equation:

C1*V1= C2*V2

In this case:

Replacing:

3 M* 0.065 L= C2*0.15 L

Solving:

C2= 1.3 M

The concentration of HI in the final solution is 1.3 M.

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!