Determine the mass of oxygen in a 45.0 g sample of calcium carbonate

The mass of oxygen in 45.0 g sample of calcium carbonate is approximately 21.58 g

Explanation:

The chemical formula for calcium carbonate is CaCO₃

The molar mass of CaCO₃ = 100.0869 g/mol

The mass of oxygen in one mole of CaCO₃ = 3 × 15.999 g = 47.997 g

The mass of oxygen in 45.0 g sample of CaCO₃, m, is goven as follows;

m = 45.0/100.0869 × 47.997 g ≈ 21.58 g

The mass of oxygen in 45.0 g sample of calcium carbonate, m ≈ 21.58 g

the answer is:  

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