I need help on this question asap! You are in a lab and you use 11.50 g of Na(s) to react with Cl(g). Below is the reaction that happens from this.

Na + Cl2 → NaCl

Your percent yield is 95%. From this info what is the actual yield?

27.79 g to the nearest hundredth.

Explanation:

2Na + Cl2 ---> 2NaCl

Using the molar masses , the theoretical yield is:

46 g of Na yields  46 + 35.5*2 g NaCl

46 g ---> 117 g NaCl  so

11.5 g > 117 * 11.5 / 46 g NaCl

But, as the yield is 90%

the actual yield is 0.95 * 117 * 11.5 / 46

= 27.79 g.