Step 5: Measure the Mass of the Water (Iron) Tare the balance. Put calorimeter (no lid) on the balance.
Measure the mass to the nearest 0.01 g. 12.26 X
12.42 g
COMPLETE
Use a graduated cylinder to add approximately 40 mL of
water to the calorimeter. Measure the mass of the calorimeter
(no lid) and water to the nearest 0.01 g. 52.49
52.66 g
COMPLETE
52.669
Subtract to find the mass of the water.

Tare the balance. Put calorimeter (no lid) on the balance.

Measure the mass to the nearest 0.01 g. 12.26 X

12.42 g

COMPLETE

Use a graduated cylinder to add approximately 40 mL of

water to the calorimeter. Measure the mass of the calorimeter

(no lid) and water to the nearest 0.01 g. 52.49

52.66 g

COMPLETE

52.669

Subtract to find the mass of the water.

idk

explanation:

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.