A cylinder container with a diameter of 23.0 cm and a height of 140 cm contains N2O at a pressure of 108 kpa and temperature of 294 K. How many grams of N2O gas are in the cylinder?

113.17 g

Explanation:

This can be solved using the Ideal Gas Equation:

PV=nRT

First step is to calculate the volume of the cylinder in L:

V=πr²h

V= π (11.5)² (140)

V= π (132.25) (140)

V = π (18.515)

V = 58,166.588 cm³ = 58.2 L

Then, convert kpa into atm:

1 kpa = 0.00987 atm

108 kpa = 1.06588 atm

Then, plug all of your values into the Ideal Gas Equation to solve for moles:

(1.06588)(58.2)=n(0.082057)(294)

62.034=n(24.125)

2.571357513=n

Finally, convert the moles into grams

2N = 28.0134 amu

O = 15.999 amu

44.0124 amu

(2.571357513moles)(44.0124 amu) = 113.17 g

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