What is the concentration of a solution formed by diluting 25.0 ml of a 3.8M glucose solution to 250ml

Explanation : số mol glucose 3.8M là :

n = Cm . V = 3.8 . 25 =95

=> Cm khi pha loãng = = = 0.38M

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

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