Cho 6,5 g Zn tác dụng với dung dịch chứa 12g HCl. Thể tích khí H2 ( ở đktc ) là

nHCl = 12/36,5= 0,38(mol)

nZn = 6,5/65 = 0,1(mol)

Ta có pt: Zn + 2HCl --> ZnCl2 + H2

Vì 2n Zn = 0,2 < n HCl = 0,38 nên HCl dư

Theo PTHH :

n H2 = n Zn = 0,1(mol)

V H2 = 0,1.22,4 = 2,24(lít)

Explanation:

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'

the answer to this question is 3.