. Determine the concentration of the Brilliant Blue working solution. Concentration of Brilliant Blue stock solution:1.27e-4 M Volume of Brilliant Blue stock solution used:7.10 mL Final volume of Brilliant Blue working solution:50.00 mL (5pts) Concentration of Brilliant Blue working solution (M): Saved 2. Determine the concentration of the Bleach working solution. Concentration of Bleach stock solution:8.25% w/v NaOCl Volume of Bleach stock solution used:1.50 mL Final volume of Bleach working solution:50.00 mL (5pts) Concentration of Bleach working solution (M):

the answer is learned

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2