The theoretical yield and the percent yield are calculated as shown. 0.222gO2 and 87.8% Did you perform the calculations correctly? Yes, I got the correct theoretical yield and percent yield. No, I got the correct theoretical yield but calculated the percent yield incorrectly. No, I calculated the theoretical yield incorrectly, so my percent yield calculation was also incorrect. No, I used the correct equations, but I got the wrong answer because of a math error.

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.