7 f Find the volume in dm3 and in mole of 0.505m of NaoH required to react with 40ml of 0.505m of H₂SO4 Solution

The volume of NaOH required is 0.08 dm³

To solve this question, we'll begin by writing the balanced equation for the reaction between H₂SO₄ and NaOH. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

Mole ratio of the acid, H₂SO₄

Mole ratio of the base, NaOH

Next, we shall determine the volume of NaOH required to react with H₂SO₄. This can be obtained as follow:

Molarity of the base, NaOH

Volume of the acid, H₂SO₄

Molarity of the acid, H₂SO₄

Cross multiply

Divide both side by 0.505

Finally, we shall convert 80 mL to dm³. This can be obtained as follow:

Therefore, the volume of NaOH required is 0.08 dm³

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