Phosphorus is directly under nitrogen in the periodic table and forms a compound similar to that of ammonia. The compound has the empirical formula PH3 and it is called phosphine. It can be prepared by the reaction: P(s) + 3NaOH(aq) + 3H20 (l) PH3(g) +3NaH2
If 0.610 g of phosphorus and 0.250 g of NaOH are reacted with H2O() in excess, how many grams of phosphine will be obtained?​

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

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