How many moles of Al2O3 are contained in 45.1 g of Al2O3?

0.44mol

Explanation:

1mol/102g=xmol/45.1g

-> x=(45.1x1)/102

x=0.44mol

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water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.