(07.05 MC) The table shows the concentration of a reactant in the reaction mixture over a period of time.
Reactant Concentration
Time
Concentration
1.8 M
Os
2105
1.2 M
450 S
0.8 M
580 S
0.6 M
720 S
0.4 M
What is the average rate of the reaction over the first 450 seconds? (3 points)
Select one:
a.1.7 x 10-3
b.1.9 x 103
c.2.0 x 109 x
d.2.2 x 10-3

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.