Consider the following reaction in aqueous solution: 5 Br (aq) + Brog (aq) + 6 H+(aq) - 3 Bro(aq) + 3 H2O(l) If the rate of disappearance of Br-(aq) at a particular moment during the reaction is 0.0470 M s-, calculate the rate of change of H-(aq) and H. O() at that moment? rate of change of H- = M s-1 rate of change of H. O(aq) = M s-1​

Ions gain or lose electrons

Answer is: the equilibrium  shifts toward the reactants, to the left side of chemical reaction.it is because lead(ii) nitrate dissociates in water: pb(no₃)₂ → pb²⁺(aq) + 2no₃⁻(aq).according to lechatelier's principle, the position of equilibrium moves to counteract thechange (more lead cations, common ion), the position of equilibrium will move so that the concentration ofproducts decrease and concentration of reactants of chemical reaction increase.read more on -

Gamma waves is the answer