For H2(g)+Br2(g)↽−−⇀2HBr(g), H 2 ( g ) + Br 2 ( g ) ↽ − − ⇀ 2 HBr ( g ) , =7.2×10−4 K = 7.2 × 10 − 4 at 1362 K and Δ∘ Δ H ∘ is positive. A vessel is charged with 50.0 Pa 50.0 Pa HBr, HBr , 1420 Pa 1420 Pa H2, H 2 , and 3345 Pa 3345 Pa Br2 Br 2 at 1362 K.