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Chemistry, 22.09.2021 08:40 bnnn

Could someone check if my answer is correct??? Equation
H2SO4(aq)+2NaOH(s)—> Na2SO4(aq)+ 2H2O(l)

2.20/39.9970= 0.05500413 which is the limiting reagent

0.05500413 mol NaOH= (2 mol H2O)/(2 mol NaOH)= 0.05500413 mol H2O

Convert moles of H2O to mass
0.05500413x18.02= 0.99117434

% yield of H2O = 0.743/ 0.99117434= 75.0%


Could someone check if my answer is correct???

Equation 
H2SO4(aq)+2NaOH(s)—> Na2SO4(aq)+ 2H2O

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