Chemistry, 25.09.2021 14:00 cjdieball2106

How many molecules are contained in 4.00g of CO2 if the Molar mass of CO2 is 44.00 g/mole?

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Answer from: reghanhoward3

5.47 × 10²² CO₂ molecules

Explanation:

We want to determine the amount of molecules of CO₂ in 4.00 grams of CO₂ given that its molar mass is 44.00 g/mol.

To convert from grams to molecules, we can first convert from grams to moles and then from moles to molecules using the following two ratios:

$\displaystyle \frac{1 \text{ mol CO$_2$}}{44.00 \text{ g CO$_2$}}\text{ and } \frac{6.02 \cdot 10^{23} \text{ molecules CO$_2$}}{1 \text{ mol CO$_2$}}$

Begin with the initial value and multiply:

$\displaystyle \begin{aligned} &4.00 \text{ g CO$_2$} \cdot \frac{1 \text{ mol CO$_2$}}{44.00 \text{ g CO$_2$}}\cdot \frac{6.02 \times 10^{23} \text{ molecules CO$_2$}}{1 \text{ mol CO$_2$}} \\ \\ &= 5.47 \times 10^{22} \text{ molecules CO$_2$}}\end{aligned}$

Note that the final result should have three significant digits since 4.00 has three sig. digs.

In conclusion, there are about 5.47 × 10²² CO₂ molecules in 4.00 grams of CO₂.

Answer from: 23gordns

$\boxed {\boxed {\sf 5.47 \times 10^{22} \ molecules \ CO_2}}$

Explanation:

We are asked to find how many molecules are contained in 4.00 grams of carbon dioxide.

1. Grams to Moles

Convert grams to moles using the molar mass (mass of 1 mole of a substance). The molar mass of carbon dioxide is given: 44.00 grams per mole.

We will convert using dimensional analysis. Set up a conversion factor using the molar mass.

$\frac {44.0 \ g \ CO_2}{ 1 \ mol \ CO_2}$

We are converting 4.00 grams of carbon dioxide to moles, so we multiply by this value.

$4.00 \ g \ CO_2 * \frac {44.0 \ g \ CO_2}{ 1 \ mol \ CO_2}$

Flip the conversion factor. The value remains the same, but it allows us to cancel the units of grams of carbon dioxide.

$4.00 \ g \ CO_2 * \frac { 1 \ mol \ CO_2}{44.0 \ g \ CO_2}$

$4.00 * \frac { 1 \ mol \ CO_2}{44.0 }$

$\frac {4.00}{44.00 } \ mol \ CO_2$

$0.09090909091 \ mol \ CO_2$

2. Moles to Molecules

Convert moles to molecules using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are molecules of carbon dioxide.

Set up another conversion factor, this time with Avogadro's Number.

$\frac {6.022 \times 10^{23} \ molecules \ CO_2}{ 1\ mol \ CO_2}$

We are converting 0.09090909091 moles of carbon dioxide to molecules, so we multiply by this value.

$0.09090909091 \ mol \ CO_2*\frac {6.022 \times 10^{23} \ molecules \ CO_2}{ 1\ mol \ CO_2}$

The units of moles of carbon dioxide cancel.

$0.09090909091 *\frac {6.022 \times 10^{23} \ molecules \ CO_2}{ 1}$

$0.09090909091 *{6.022 \times 10^{23} \ molecules \ CO_2}$

$5.47454545 \times 10^{22}} \ molecules \ CO_2$

3. Significant Figures

The measurement of molar mass (44.00) has 4 sig fig and the measurement of molecules (4.00) has 3 sig fig. We round to the least number of sig fig, or 3.

For the number we found, that is the hundredth place. The 4 in the thousandth place tells us to leave the 7.

$5.47 \times 10^{22} \ molecules \ CO_2$

4.00 grams of carbon dioxide contains 5.47 × 10²² molecules of carbon dioxide.

Answer from: Quest

the answer is symmetrical : )

Answer from: Quest

I’m really not sure what’s the answer. sorry

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