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Chemistry, 30.09.2021 08:20 asapjvzz8786
What is the equilibrium expression for the reaction below?
2Na(s) +0,92NaO(S)
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Answers: 2
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What is the equilibrium expression for the reaction below?
2Na(s) +0,92NaO(S)
...
2Na(s) +0,92NaO(S)
...
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