307 g of Na3PO4 is mixed with 227 g of CaCl2. The reaction that occurs is given by the unbalanced chemical equation shown below:

2 Na3PO4 (aq) +3CaCl2 (aq) → Ca3(PO4)2 (s) +6NaCl (aq)

(a) Which reactant is limiting?

(b) How many grams of Ca3(PO4)2 are produced?

(c) If 150. g of Ca3(PO4)2 are recovered on the filter paper, what is the percent yield?

Answer asap need it by wednesday morning carry out the following calculations on ph and ka of from data. i. calculate the ph of 0.02m hcl ii. calculate the ph of 0.036m naoh iii. calculate the ph of 0.36m ca(oh)2 iv. calculate the ph of 0.16m ch3cooh which has ka = 1.74 x 10-5 mol dm-3 v. calculate ka for weak acid ha which has a ph of 3.65 at 0.30m concentration vi. calculate the ka of a solution made by mixing 15.0 cm3 0.2m ha and 60.0 cm3 0.31m a-. [ph= 3.80] vii. calculate the ph of a solution made by mixing 15.0 cm3 0.1m naoh and 35.0 cm3 0.2m hcooh. [ka = 1.82 x 10-4 m]