When an ice cube melts in your hand, it changes from a solid to a liquid. H2O (s) → H2O (l)

This is an example of _ reaction, because heat is _ the system.

a. endothermic; leaving
b. exothermic; entering
Selected: c. exothermic; leavingThis answer is incorrect.
d. endothermic; entering

Which situation would react faster and why?
a. Example B would be faster because of a high surface area.
b. Example A would be faster because of a high surface area.
Selected: c. Example A would be faster because of a low surface area. This answer is incorrect.
d. Example B would be faster because of a low surface area.

Balance the following the chemical equation:

_ Ti3N + _ MgO → _ Mg3N2 + _ Ti2O

Balance the following the chemical equation:

_ Incorrect. Ti3N + _ Incorrect. MgO → _ Incorrect. Mg3N2 + _ Incorrect. Ti2O

Balance the following the chemical equation:

_ N2 + _ O2 → _ NO

Balance the following the chemical equation:

N2 O2 → NO

Looking at the periodic table, determine the charge each atom will make when it bonds with other atoms.
Calcium (Ca)

2.

Francium (Fr):

Francium (Fr)
3.

Bromine (Br):

Bromine (Br)
4.

Sulfur (S):

Sulfur (S)
5.

Xenon (Xe):

Xenon (Xe)
6.

Carbon (C):

Carbon (C)
7.

Phosphorous (P):

Phosphorous (P)
8.

Boron (B):

Boron (B)

Column B
a. -1
b. -3
c. +4/-4
d. +3
e. +1
f. -2
g. 0
h. +2

30litre of li2o is 1.0002mole approximately 1 mole

16- counting by fours

The water cycle increase the water content in the earth atmosphere

Note that 2 mol dm⁻³ = 2 mol/(dm³)outline: we're given the concentration of hcl, which is  2 mol dm⁻³ (cubic meters in the denominator can represent volume, so i know this is concentration). we're an amount of calcium carbonate caco₃, which is 5 g. we're presented with a chemical equation which includes caco₃ and hcl. we are told to find the volume of hcl. from what we see so far, this seems to be a stoichiometry  problem. we'll have to use the given information about calcium carbonate to find the amount of moles of hcl needed to fully react with calcium carbonate. then we'll have information about the moles of hcl and the concentration of hcl; that will be enough to figure out volume according to the formula concentration = moles / volume.======all the answer choices are not in dm.convert the given concentration so that it uses cm⁻³.we can use conversion factors. we have to cube our conversion factors so that dimensional analysis works.we can convert to meters first, using the fact that     10 dm = 1 m  ⇔ 10³ dm³ = 1 m³then we use the fact that     10² cm = 1 m ⇔ (10² cm)³ = (1 m)³ ⇔ 10⁶ cm³ = 1 m³so converting:     now we have to find the moles of hydrochloric  acid neededfind the moles of calcium carbonate. we have to find the molar mass of calcium carbonate, caco₃, which can be found by    molar mass = (mass ca) + (mass c) + 3(mass o)    = 40 + 12 + 3(16)    = 100 g/molconvert the given 5 g to moles:     mol caco₃ = 5 g caco₃ * 1 mol/(100 g) = 0.05 mol caco₃use stoichiometry (ratios) to figure out the moles of hcl needed. ratio wise, there's 2 hcls for every caco₃, so use dimensional analysis    mol hcl = mol caco₃ * (2 mol hcl) / (1 mol caco₃)    = 0.05 mol hcl * 2    = 0.1 mol hcl  we have 0.1 mol hcl and concentration of hcl (0.002 mol/cm³).we need to find volumesince concentration = moles / volume, rearrange to get     volume = moles / concentration    volume = 0.1 mol / (0.002 mol/cm³)    volume = 50 cm³