A student needs to make 0.855 L of a sodium bromide solution for an experiment. The concentration of the required solution is 0.350 M. How many grams of sodium bromide will he need to use?

Explanation:

Molarity =  moles/liters of solution

moles    = molarity x Liters of solution

            =  0.350 m/L x 0.855 L

            =  0.299 mol

               mass = moles  x  molar mass    

            = 0.299 mol x 102.89 g/ms

            =  30.78 grams

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