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[ lesson : molarity ]

18) What is the molarity of a bleach solution containing 9.5 g of NaOCI per liter of bleach?

19) How much calcium hydroxide (Ca(OH)2) in grams, is needed to produce 1.5 L of a 0.25M solution

Q1) 0,1276 M

Molair mass of NaOCl = 74,44 g/mol

You have 9,5 g/L.

You need to calculate with the molar mass, how many moles 9,5 g are:

9,5 g / 74,44 g/mol = 0,1276 molAR

0,1276 mol / 1 L = 0,1276 M

Q2) 27.78  grams

The  mass    ca(Oh)2  needed  to  produce  1.5 l  of  0.25 solution  is  calculated  as follows

find  moles

=moles   = molarity   x  volume

moles is therefore =   1.5  x 0.25  =  0.375  moles

mass  =  moles  x  molar  mass

0.375mol  x  74.09 g/mol  =  27.78  grams

Explanation:

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