WILL GIVE BRAINLIEST AND 20 POINTS! Barium hydroxide, often used to titrate weak organic acids, is obtained as the octahydrate, Ba(OH)2 * 8 H2O. What mass of Ba(OH)2 * 8 H2O would be required to make 500 mL of a solution that is 0.1500 M hydroxide ions? [hint: calculate the molar mass of barium hydroxide octahydrate].

11.83g or 11.83 g Ba(OH)2.8H2O

Explanation:

Here we have to calculate the mass  of Ba(OH)2 • 8H2O would be required to make 500.0 mL of a solution that is 0.1500 M in hydroxide ions.

Given:

Volume of Ba(OH)2 • 8H2O = 500.0 mL or 0.5000 L

Concentration of OH- ion = 0.1500 M

Molecular mass of Ba(OH)2 • 8H2O = 315.4 g

Thus the mass can be calculated as,

0.500L × × ×  

= 11.83 g Ba(OH)2.8H2O

Thus the mass of Ba(OH)2 • 8H2O is found to be 11.83 g .

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.