19 What is the number of moles of nitrogen gas which react with 18 g of magnesium to form magnesium nitride compound ? [Mg = 24,N=14] a) 0.25 mol 0 b) 0.5 mol C) 1 mol d) 2 mol

0.5 mol of nitrogen gas.

Explanation:

18g of Magnesium in mol is equal to 18g/24 gmol-1 = 0.75 mol and 7g of nitrogen in mol is equal to 7g/14 gmol-1 = 0.5 mol,

Thus, When 18g of magnesium reacts with 7g of nitrogen it implies 0.75 mol of magnesium which reacts with 0.5 mol of nitrogen. :)

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

i think it is true since you can test the answer and can use observations to complete it.