(b) A student states, "When the alcohol sample was at a temperature of 500 K, all the particles were moving faster than any of the particles were moving at 400 K." Do you agree or disagree
with this student's statement? Justify your answer.
B
I
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alel
(c) Using boxes like the ones below, draw three particle diagrams representing the sample of
alcohol cooling in this experiment. The diagrams should represent the sample at 3 minutes, 12
minutes, and 17 minutes.
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09:50

the answer is 0.8m.

by: nicholas

idk what is it? is this a question that you know the answer or u dont

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied