How many molecules are in 8.27 mol of SiH,?

from,

moles,n = number of particles, N

Avogadro constant

N = 8.27 * 6.022×10^23

N = 4.98 × 10^ 24particles.

In 8.27 moles of SiH, there are

4.98 × 10^24particles.

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