I know the answer, I just don't know how my teacher got it. Can anyone teach me how to solve it please. How many moles of oxygen are present in 0.798 moles of Mg(IO3)2?
4.79 mol

About 4.79 moles of oxygen.

Explanation:

We want to determine the amount of moles of oxygen are present in 0.798 moles of Mg(IO₃)₂.

From the chemical formula, we can see that there are six atoms of oxygen for every molecule of Mg(IO₃)₂. Therefore, we can say that there are six moles of oxygen for every mole of Mg(IO₃)₂. This yields the following ratio:

Multiplying this by the initial value yields:

In conclusion, there are about 4.79 moles of oxygen present in 0.798 moles of Mg(IO₃)₂.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

i just learnt this recently but i need to look through my notes again