The equilibrium constant for the following reaction is 3.0: N2(g) + 3 H2(g) = 2 NH3(g)

Enough NH3 was added to a 5.0 L container such that at equilibrium, the container was
found to contain 2.5 mol of N2. How many moles of NH3 were put into the container? Solve using the ICE table.

Answer:

5.6⋅10−^19  j

do you need the explaination?

It's potassium i believe

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60.66% is the answer