What is the mass of solute dissolved in 10.0 g of 5.00% Sugar solution? A. 0.900 g
B. 0.180 g
C. 10.0 g D. 0.500 g
E. 9.50 g

0.5 g  or D

Explanation:

what is the mass of solute dissolved in 10.0 g of 5.00% Sugar solution?

A. 0.900 g

B. 0.180 g

C. 10.0 g

D. 0.500 g

E. 9.50 g

5% of the solution is sugar

o 10 g of the solution will have 9.5 g H2O and  0.5 g of sugar

0.5 /(9.5 +0.5) = 0.5/10 = 0.05 = 5 PER HUNDRED = 5%

so 0.5 g  or D

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

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