Calculate the change of enthalpy for the reaction 2Al (s) + 3Cl2 (g) --> 2AlCl3 (s) from the following reactions:
Reaction 1: 2Al (s) + 6HCl (aq) --> 2AlCl3 (aq) + 3H2 (g) Change in enthalpy: -1049 kJ
Reaction 2: HCl (g) --> HCl (a Change in enthalpy: -74.8 kJ/mol
Reaction 3: H2 (g) + Cl2 (g) --> 2HCl (g) Change in enthalpy: -1845. kJ/mol
Reaction 4: AlCl3 (s) --> AlCl3 (aq) Change in enthalpy: -323. kJ/mol
Include the following:
The numerical answer with correct units.
State which reactions, if any, you had to "Flip".
State which reactions you had to multiply, if any, to get the correct amount of the compound.
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