Students are to balance this equation correctly using the lowest possible values of whole number coefficients. In this case, the coefficient in front of Al(NOg) will be- ??

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.