Please Help Will Mark Brainliest!!! Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L.

In three to five sentences, explain how you can find the mass of the ammonia. Then, given R=0.0821L⋅atmmol⋅K, calculate the mass.

3.17 grams.

Explanation:

First of all, you need to explain the formula you are going to use. (This does not count as 1 of your 3 sentences).

The formula is

P*V = n*R*T

You know what P and V are on the left

P = 1.2 atmospheres

V = 3.7 Liters

You are looking for n (mols)

On the right, you know what R and T are. So you take the product of R and T and divide into the product of P and V

When you know n, you can use the molar mass to find the actual mass. You can condense this any way you like. I'm more concerned about your understanding.

P*V = 1.2 * 3.7 = 4.44

R*T = 0.0821 * 290 = 23.809

PV/RT = n

4.44 / 23.809 = 0.1865

1 mole of Ammonia gas = 17 grams

0.1865 mol = x                                    Cross multiply

x = 17 * 0.1865

x = 3.17   grams of Ammonia.

4

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied