A natural gas mixture having a molar analysis 40% C3H8 and 60% CH4 burns completely with 100% of excess air. Determine a balanced chemical equation, assuming 10 kmoles of fuel. Please keep two decimal points at most for answers in this part (i. e. 4 and 3.5 are OK but 6.156 needs to rounded to 6.16).

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o