Part D Calculate the following for test tube 1 and for test tube 2, and record the results in the table:
• the number of moles of copper(II) sulfate used (Use 159.60 grams/mole as the molar mass of copper(II)
sulfate.)
• the heat absorbed by the water, in joules (Use Q = mCAT, where 10.0 milliliters of water has a mass of 10.0
grams. Use 4.186 joules/gram degree Celsius as water's specific heat capacity.)
• the change in internal energy of the copper(II) sulfate (Assume that the energy released by the copper(ll)
sulfate is absorbed by the water.)
• the reaction enthalpy, in joules/mole

Asample of ammonia reacts with oxygen as shown. 4nh3(g) + 5o2(g) 4no(g) + 6h2o(g) what is the limiting reactant if 4.0 g of nh3 react with 8.0 g of oxygen? o2 because it produces only 0.20 mol of no. nh3 because it produces only 0.20 mol of no. o2 because it produces two times less no than nh3. nh3 because it produces three times more no than o2.

At 300 mm hg, a gas has a volume of 380 l, what is the volume at standard pressure

Which explanation is true about what happens to a ray of light when it strikes a mirror? a. a light ray is transmitted toward a mirror at a certain angle. the light ray is then reflected by the mirror at an equal angle but in the opposite direction of the transmitted ray. b. an incident ray strikes a mirror at an angle with a line perpendicular to the mirror. the light ray is then reflected at an angle equal to the angle of incidence but on the opposite side of the perpendicular line. c. a reflecting ray strikes a mirror at an angle with a line perpendicular to the mirror. the light ray is then refracted at an angle equal to the angle of the reflecting ray and on the same side of the perpendicular line. d. an incident ray strikes a mirror at an angle with a line parallel to the mirror. the light ray is then transmitted at an angle equal to the angle of incidence but on the opposite side of the parallel line. you so much! : -d take the time to try and answer correctly.