When lumps of calcium carbonate react with hydrochloric acid, carbon dioxide gas is released according to the equation shown below. CaCO3(s) + 2HCl(aq) > CaCl2(aq) + CO2(g + H2O(l)

What effect will the following have on the rate of the reaction?
i. Increasing the temperature.
ii. Using powder calcium carbonate instead of lumps.
iii. Use of catalyst.
iv. Adding water to the acid.

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option c: 1605.1 kj

the balanced chemical reaction for combustion of methane is as follows:

here, enthalpy formation of is -74.7 kj/mol, 0 kj/mol, -393.5 kj/mol and -241.82 kj/mol respectively.

the heat released or can be calculated as follow:

putting the values,

thus, heat released by combustion of 1 mol of methane is 802.54 kj/mol. thus, for 2 mol, heat released will be:

therefore, heat released by the combustion of 2 mol of methane is 1605.1 kj.