The boiling point of benzene is 80ºC. Which pair of samples will have the same average kinetic energy as benzene molecules? · a sample of liquid benzene at 80ºC and a sample of gaseous benzene at 80ºC

· two samples of gaseous benzene, one at 80ºC and the other at 90ºC

· a sample of liquid benzene at 70ºC and a sample of gaseous benzene at 90ºC

· two samples of liquid benzene, one at 70ºC and the other at 80ºC

Where is the following?

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

Ibelieve it's temperature! i'm not 100% sure.