Chemistry, 04.12.2021 01:10 Isabelcastillox1085
A 0.04365 g0.04365 g sample of gas occupies 10.0 mL at 291.5 K291.5 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C25.305% C and 74.695% Cl.74.695% Cl. What is the molecular formula of the compound
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A 0.04365 g0.04365 g sample of gas occupies 10.0 mL at 291.5 K291.5 K and 1.10 atm. Upon further ana...
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